WebClick here👆to get an answer to your question ️ Ozonolysis of C7H14 gave 2-methyl-3-pentanone. The alkene is O 2-ethyl-3-methyl-1-butane O 3-ethyl-2-methyl-3-butane 2,5-dimethyl-3,4-dimethyl-3-ene 3-ethyl-2-methyl-1-butane. Solve Study Textbooks Guides. Join / Login >> Class 11 WebThe IUPAC names of the products obtained by the ozonolysis of 3, 4 - Dimethylhept - 3 - ene are (I) butan-2-one and (II) pentan-2-one.
Write IUPAC names of the products obtained by the ozonolysis of …
WebWrite IUPAC names of the products obtained by the ozonolysis of the following compounds: (i) pent-2-ene (ii) 3,4-dimethylhept-3-ene (iii) 2-ethylbut-1-ene (iv) 1-phenylbut-1-ene Solution. Question 5. An alkene A on ozonolysis gives a mixture of ethanal and pentan-3-one. Write the structure and IUPAC name of A. Solution. Question 6. WebApr 8, 2024 · Write IUPAC names of the products obtained by the ozonolysis of the following compounds (i)Pent-2-ene (ii)3,4-Dimethylhept-3-ene (iii)2-Ethylbut-1-ene (iv) 1-Phenylbut-1-ene. ... Therefore, the answer is that 3-ethylpent-2-ene on ozonolysis gives a mixture of ethanal and pentan-3-one. You can find more answers to similar questions on that … lantiojumppa
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WebJun 18, 2024 · Question 4. Write the IUPAC names of the products obtained by the ozonolysis of the following compounds : (i) Pent-2-ene (ii)3, 4-dimethylhept-3-ene (iii) 2-Ethylbut-l-ene (iv) 1-Phenylbut-l-ene. Answer: Question 5. An alkene ‘A’ upon ozonolysis gives a mixture of ethanal and pentan-3-one. Write the structure and IUPAC name of ‘A’. Answer: WebQuestion 4. Write IUPAC names of the products obtained by the ozonolysis of the following compounds: (i) Pent-2-ene (ii) 3, 4-Dimethylhept-3-ene (iii) 2-Ethylbut-l-ene (iv) 1-Phenylbut-l-ene. Answer: Question 5. An alkene ‘A’ on ozonolysis gives a mixture of ethanal and pentan-3-one. Write the structure and IUPAC name of ‘A’. Answer: Step 1. WebJan 23, 2024 · The products of ozonolysis will vary depending on two things: 1) The R groups that are attached to the alkene: 1. Ends of alkenes with –R groups on both sides = Ketones 2. Ends of alkenes with 1 –H = Aldehydes 3. Ends of alkenes with 2 –Hs (yielding single carbon fragments) = Formaldehyde assistant a\u0026r jobs